3.3 Marginal functions
(Section 4.3 of Jacques)
· Calculate marginal revenue and marginal
cost
· Calculate marginal product of labour
· Study the law of diminishing returns
· Partial derivatives
3.3.1 Revenue and cost
Recall:
Total
revenue is
TR = P´ Q
where P is the price of a good and Q is quantity demanded
Given a
demand function, e.g.
P = 100 - 2Q
we can write
TR in terms of Q:
TR = PQ
= 100Q - 2Q2.
In order to
study how TR reacts to a small change in Q, we look at the derivative of TR with respect to Q.
DEFINITION:
Marginal
revenue MR is the derivative of total revenue
with respect to demand. That is,
.
Example:
In the
example above, we had
TR = 100Q - 2Q2.
Differentiating
gives
MR = 100 - 4Q.
This formula
allows us to calculate MR at any value of Q.
NON-CALCULUS
DEFINITION
In some
books, MR is defined as
the
change in the value of TR brought about by a one
unit increase in the value of demand Q.
This
definition approximates the slope of the graph of TR
(i.e. the tangent slope) by the slope of a nearby line which cuts the curve at two
points. However this approximation is not always accurate.
The
definition of differentiation tells us that
.
So if DQ is small, then
. (*)
In
particular, if DQ
= 1, this gives the non-calculus version of MR:
.
If we read
equation (*) from right to left, we see that we can use MR to predict
the change in TR brought about by a small change
in demand Q:
![]()
or
change in total revenue ~ marginal revenue X change in demand
Example
Given the
demand function P = 60 - Q, calculate TR and then
(1)
find MR in terms of Q, and evaluate MR at Q = 50.
(2)
Calculate TR at Q =
50 and at Q = 51 and hence confirm that the
one-unit-increase approach gives a reasonable approximation to the exact value of MR.
Solution: We
have
TR = PQ = (60 - Q)Q = 60Q - Q2.
(1)
Differentiating
this expression gives
.
When Q = 50, this gives
MR = 60 - 2(50) = -40.
(2)
When Q = 50, TR
= 60(50) - (50)2 = 500.
When Q = 51, TR = 60(51) - (51)2 = 459.
Then using
the approximation formula
,
we get
MR ~ 459 - 500 = -41,
which is a
good approximation to the actual value of -40.
Example
The total
revenue of a good is
TR = 100Q - Q2.
Write down
an expression for marginal revenue.
If the
current demand is Q=60, estimate the change in TR brought about by a 2 unit increase in Q.
Solution
Differentiating
gives
MR = 100 - 2Q.
At Q = 60, this gives
MR = -20
Now we use
the formula
![]()
This
predicts that the change in TR will be
D(TR)
~ -20 ´ 2 = -40.
A two-unit
increase in demand leads to a 40 unit decrease in total revenue.
Exercise
The total
revenue function for a good is given by
TR = 1000Q - 4Q2.
Write down
an expression for the marginal revenue.
If demand is
currently 30, estimate the change in TR due to
a
(1)
three-unit increase
in Q
(2)
two-unit decrease
in Q
What we have
done here for total revenue can be done for any economic function. For example, given the
total cost function TC, we define the marginal cost MC by

marginal cost is the derivative of
total cost
with respect to output Q
Just as we
did for revenue, we can derive the approximation
change in total cost ~ marginal cost X change in output
Exercise
Find the
marginal cost given the average cost function
.
If the
current output is 15, estimate the effect on TC of
a three-unit decrease in Q.
(Remember
that
.)
3.3.2 Production
We studied
production functions of the form
Q = f(K,L),
i.e. the
production function f determines output Q in terms of labour L and capital K.
Here, we
will consider the case where K does not change,
so that Q depends only on L:
Q = f(L).
Then the
derivative of Q with respect to L tells us how Q reacts to changes in L. This derivative is called marginal product of labour:
.
marginal product of labour is the
derivative of output
with respect to labour.
As usual,
change in output ~ marginal product of labour X
change in labour
Example
If the
production function is
Q = 300ÖL - 4L,
calculate
the value of MPL when
(a)
L = 1
(b)
L = 9
(c)
L = 100
(d)
L = 2500.
Comment on
the results.
Solution
We have
Q = 300 L1/2 - 4L
so
![]()
(a)
When L = 1,
![]()
(b)
When L = 9,
![]()
(c)
When L = 100,
![]()
(d)
When L = 2500,
![]()
Thus we see
that MPL is decreasing, and
eventually becomes negative.
Thus the size of the increase in output brought about by a
one-unit increase in labour L is decreasing.
Worse still,
at the stage when MPL < 0, an
increase in labour L would cause a decrease in output Q.
This is what
we would expect in the real world; problems such as overcrowding on the workshop floor and
administrative overheads decrease the efficacy of increasing the size of the workforce.
This example
illustrates the law of diminishing marginal
productivity (also known as the law of
diminishing returns).
"The increase in output due to a
one-unit increase in labour will eventually decline"
Translating
this into maths, we obtain
the marginal product of labour MPL will eventually be a decreasing
function.
That is, for
sufficiently large values of L, we should have
![]()
Since we
know that MPL is the derivative of
output Q, we can write this as

Summary:
To show that
a production function satisfies the law of diminishing returns, we must show that

holds for
all sufficiently large values of L.
Example
Show that
the Cobb-Douglas production function
Q = 5L1/2K1/2,
with K = 100, satisfies the law of diminishing returns.
3.3.3
Partial Derivatives
(cf.
Jacques, Section 5.2)
Q = 5L1/2K1/2.
This
depends on both L and K.
If we take
K to have a
fixed value and allow L to vary, we
can analyse changes in Q by looking
at the derivative dQ/dL.
Similarly,
If we take L to have a
fixed value and allow K to vary, we
can analyse changes in Q by looking
at the derivative dQ/dK.
To
emphasise the fact that Q depends
on both variables, we call these derivatives partial derivatives and use a
different notation:
=
derivative of Q with
respect to L, holding K constant.
=
derivative of Q with
respect to K, holding L constant.
Example:
(i)
Calculate
and
for the Cobb-Douglas function
Q = 5L2K3/2.
(ii) If
the current values are L=10, K = 12, which
would bring about a bigger increase in Q:
increasing L by one
unit, or increasing K by one
unit?
3.3.4Consumption
and Savings
Y =
national income, C = consumption, S = savings connected
by Y= C + S
To
analyse changes in C and S due to changes in Y use marginal
propensity to consume MPC and marginal
propensity to save MPS.
![]()
These
agree with the special case of linear consumption and savings curves given earlier.
We
can find MPC given MPS (or vice versa): we know
that
Y =
C + S
Ddifferentiate
both sides with respect to Y:
1 =
MPC + MPS
Example: Given
C =
0.01Y2+0.2Y + 50
Find
MPC and MPS when Y=30.
![]()
When
Y=30,
MPC
= 0.02(30) + 0.2 = 0.8
To
find MPS: MPC + MPS = 1 =>
MPS
+ 0.8 = 1 => MPS = 0.2
3.4
Elasticity
Elasticity
deals with the sensitivity of demand (supply) to changes in price. Remember that TR = P´Q and
in our models, P decreases => Q increases.
Change
in TR depends on percentage changes in P and
Q.
Demand
is said to be elastic, if the percentage change in Q is higher
than the percentage change in P.
Then
we can increase revenue by lowering price.
Demand
is said to be inelastic, if the percentage
change in Q is lower than the percentage change in P.
Then
we can increase revenue by raising price.
E =
- (% change in demand)
(%
change in price)
Minus
sign is a convention to ensure E > 0.
Demand
is
· inelastic
if
E < 1
· unit
elastic if
E = 1
· elastic
if
E > 1
Change
in P = DP,
change in Q = DQ
%
change in P = 100 (DP/P)
%
change in Q = 100 (DQ/Q)

Elasticity
at P:
Let
the arc PQ shrink down to P by moving Q closer to P
Thus
DP
and DQ
shrink to zero and
![]()
Price
elasticity of demand at a point is given by

Demand
function is usually P = f (Q);

To
find
, we use
.
Example:
Given the demand function
P =
- Q2 - 4Q + 96,
(i)
Find price elasticity of demand when
P = 51.
(ii)
If this price rises by 2 %, find the corresponding percentage
rise in demand.
First,
find Q corresponding to P = 51
- Q2
- 4Q + 96 = 51
roots:
Q = - 9 (reject), Q = 5.
Next,
we calculate
.
= -2Q - 4 => 
Q =
5 gives
= -1/14
Elasticity:

(ii)
recall that:

We
found E = 0.73, we are told (% change in P) =
2. Thus
![]()
=>
% change in Q = - 1.46 %
Q
decreases by 1.46 %

or
